r gsub vector

Wet Feet; 2013-10-17 10:52; 6; As the title states, I am trying to use gsub where I use a vector for the "pattern" and "replacement". I tried looking at the different apply()s but am not getting anywhere, partly because I lack the mental flexibility to combine the fact that I am applying gsub() to y but now want to apply that to x ... erm. grep, grepl, regexpr, gregexpr and regexec search for matches to argument pattern within each element of a character vector: they differ in the format of and amount of detail in the results. I leave it as an exercise to figure out why not. In case you have further questions, don’t hesitate to let me know in the comments section below. Note, however, that this will **not** work if the "something else" regular expression itself contained elements of x in the "wrong" order. For regexpr an integer vector of the same length as text giving the starting position of the first match, or -1 if there is none, with attribute "match.length" giving the length of the matched text (or -1 for no match). multigsub - A wrapper for gsub that takes a vector of search terms and a vector or single value of replacements.. sub_holder - This function holds the place for particular character values, allowing the user to manipulate the vector and then revert the place holders back to the original values. In this post you learned how to select numerics from a character string array in the R programming language. For sub and gsub a character vector of the same length as the original. Gsub a every element after a keyword in R, gsub function replaces all matches of a string, if the parameter is a string vector, returns a string vector of the same length and with the same attributes (after possible coercion to character). sub and gsub perform replacement of the first and all matches respectively. R: gsub, pattern = vector and replacement = vector. A vector of filename extensions (without the leading periods). grep(value = TRUE) returns a character vector containing the selected elements of x (after coercion, preserving names but no other attributes). Actualmente, tengo un código que se ve así: grepl returns a logical vector (match or not for each element of x). R: gsub, patrón = vector y reemplazo = vector Como dice el título, estoy t r atando de usar gsub donde uso un vector para el “patrón” y “reemplazo”. sub & gsub R Functions; Extract Substring Before or After Pattern; Find Position of Character in String; The R Programming Language . :/ Marianne-- mimetype A regular expression to filter files based on their MIME types, e.g., '^text/' for plain text files. While grep() and grepl() were used to simply check whether a regular expression could be matched with a character vector, sub() and gsub() take it one step further: you can specify a replacement argument. I don't now whether or not this is less "kludgy" than the explicit loop (loops are implicitly used anyway), but Reduce(function(x1,x2)gsub(x2,"something else",x1),x, init=y) does it using gsub. y <- gsub(x[i],"something else",y)} Surely, there must be a less kludgy way? Multiple gsub. https://www.datasciencemadesimple.com/sub-gsub-function-in-r For sub and gsub return a character vector of the same length and with the same attributes as x (after

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